MATH 110 Exam 8 Statistics-2021-2022

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Exam Page 1 Suppose we have independent random samples of size n1 = 420 and n2 = 510. The proportions of success in the two samples are p1= .38 and p2 = .43. Find the 99% confidence interval for the ... difference in the two population proportions. n1=420 n2=510 p1=.38 p2=.43 z=2.58 P1 - P2 ± z √p1 (1 - p1) + p2 (1 - p2) n1 n2 .38 - .43 ± 2.58 √.38 (1 - .38) + .43 (1 - .43) 420 510 -.05 ± 2.58(.03227) So the interval is ( -.1332566 .0332566 ) Instructor Comments Very good. Answer Key Exam Page 2 In certain hospital, nurses are required to constantly make rounds to check in on all of the patients. The nursing supervisor would like to know if there is a difference between the number of rounds completed per shift by the nurses on the day shift compared to the nurses on the night shift. So, the nursing supervisor checks the records of 61 day shift nurses and finds that they complete an average (a mean) of 39 rounds per shift with a standard deviation of 6.1 rounds per shift. The nursing supervisor also checks the records of 49 night shift nurses and finds that they complete an average (a mean) of 29 rounds per shift with a standard deviation of 5.2 rounds per shift. CONTINUED....... [Show More]

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