Micro Biology > QUESTIONS & ANSWERS > University of Illinois, Urbana ChampaignMCB 354MCB354FA16_PS02_KEY IN LINE WITH NEW SYLLABUS 2021 (All)
Question 1 The PDB file for Ca2+-bound calmodulin (PDB code 1EXR) was determined from a crystal with unit cell dimensions a = 25.0 Å, b = 29.4 Å, and c = 52.8 Å. The X-ray source had a wavelengt... h of 0.886 Å. Considering only diffraction planes parallel with the b-c plane, i.e. Miller indices (h 0 0), give the diffraction angle for the first and second order reflections. Bragg’s Law: 2 d sin = n The spacing between diffraction planes is equal to the unit cell dimension a = 25.0 Å. For the first order reflection: 2 25.0 sin = 1 0.886 and therefore = 1.02 For the second order reflection: 2 25.0 sin = 2 0.886 and therefore = 2.03 The diffraction angles (diffraction angle = 2) are 2.04 and 4.06. [Show More]
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